- BaseTask.GetResult中成功返回结果后,结果在任务中会被删除(以免被管理的任务不必要的HOLD住对象)
This commit is contained in:
@@ -169,6 +169,7 @@ func (t *BaseTask) GetID() string {
|
||||
return t.ID
|
||||
}
|
||||
|
||||
// 此函数成功返回结果后,结果在任务中会被删除(以免被管理的任务不必要的HOLD住对象)
|
||||
func (t *BaseTask) GetResult(duration time.Duration) (retVal []interface{}, err error) {
|
||||
if t.GetStatus() >= TaskStatusEndBegin {
|
||||
return t.getResult(), t.GetErr()
|
||||
@@ -279,10 +280,12 @@ func (t *BaseTask) GetNoticeMsg() string {
|
||||
return t.NoticeMsg
|
||||
}
|
||||
|
||||
func (t *BaseTask) getResult() []interface{} {
|
||||
t.locker.RLock()
|
||||
defer t.locker.RUnlock()
|
||||
return t.Result
|
||||
func (t *BaseTask) getResult() (result []interface{}) {
|
||||
t.locker.Lock()
|
||||
defer t.locker.Unlock()
|
||||
result = t.Result
|
||||
t.Result = nil
|
||||
return result
|
||||
}
|
||||
|
||||
func (t *BaseTask) AddBatchErr(err error) {
|
||||
|
||||
Reference in New Issue
Block a user